5 pencil and 7 pens together cost 50 where as 7 pencil and 5 pens together cost 46 .find the cost of one pencil and pen .find there solutions graphically.
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Answer:
Cost of one pencil = Rs. 3 and that of one pen = Rs. 5
Step-by-step explanation:
cost of pencil = x
cost of pen = y
5 pencil + 7 pens = Rs. 50
5x + 7y = Rs.50
5x = 50-7y
x = 10 − 5/7y
Plug value of y which is factor of 5 to get whole number so plug y=5,10,15 we get for y = 5
x=10−5/7
y=10−7=3
for y=10
x=10−5/7
y=10−14=−4
for y = 15x = 10−5/7
y=10−21=−10
Therefore, the required points are (3,5),(−4,10),(−11,15).
Given that 7 pencils and 5 pens together cost Rs. 46
7x+5y=46
Subtract 7x both side we get
5y=46–7x
Divide by 5 we get
y=9.2–1.4x
Plug x=0,2,4 we get
for x=0
y=9.2–0=9.2
for x=2
y=9.2–2.8=6.4
forx=4
y=9.2–5.6=3.6
Therefore, the required points are (0,9.2),(2,6.4),(4,3.6).
the point of intersection is (3,5),
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