Question

5. Pencils are sold in boxes containing 10
pencils each and notebooks are sold in
packets containing 12 notebooks each.
How many boxes of pencils and packets
of notebooks at least should Ariv purchase
so that he has equal number of pencils and
notebooks ?​

Answer 1

Given:

No of pencils in a box = 10

No of notebooks in a packet = 12

To Find:

The minimum number of boxes of pencils and packets of notebooks so that both are equal.

Calculation:

- Let the no of pencil boxes be x and the no of notebook packets be y.

- Then according to the question:

10 x = 12 y

⇒ x = 12/10 y

⇒ x = 1.2 y

- Using the hit and trial method, we get:

x = 6 and y = 5

So that the no of pencils and notebooks become 60.

- So, 6 boxes of pencils and 5 packets of notebooks must be purchased by Ariv to get equal no of pencils and notebooks.

Answer 2

Answer:

6 pencil boxes

5 notebook packets

Explanation:

verified method

HOPE IT HELPS