Question

5) Perimeter = cm Perimeter am 7 8) Perimeter = on 2) Perimeter = 11) H Perimeter cm Perimeter am​

Answer 1

Answer:

Perimeter of the rectangle = PQ + QR + RS + SP

= b +l + b + l

= 2b +2l

Again,

ABCD is a rectangle. We know that the opposite sides of a rectangle are equal.

Perimeter of a Rectangle

AB = CD = 5 cm and BC = AD = 3 cm

So, the perimeter of the rectangle ABCD = AB + BC + CD + AD = 5 cm + 3 cm + 5 cm + 3 cm = 16 cm

It can be written as 5 cm + 5 cm + 3 cm + 3 cm

= (2 × 5) cm + (2 × 3) cm

= 2 (5 + 3) cm

= 2 × 8 cm

= 16 cm

We add length and breadth twice to find the perimeter of a rectangle.

Perimeter of a rectangle = 2 (length + breadth)

Answer 2

Answer:

Perimeter = Sum of all side

= 4 + 2 + 1 + 5

= 12 cm

Perimeter of fig(a) is 12 cm

(b) Perimeter = Sum of all side

= 23 + 35 + 40 + 35

= 133 cm

Perimeter of fig(b) is 133 cm.

(c) Perimeter = Sum of all side

= 15 + 15 + 15 + 15

= 60 cm

Perimeter of fig(c) is 60 cm.

(d) Perimeter = Sum of all sides

= 4 + 4 + 4 + 4 + 4

= 20 cm