Math, asked by Anonymous, 1 year ago

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Answered by Anonymous
3
x^3 - x - 2x +2

x( x^2 -1) -2( x-1)

x( x-1)(x+1) -2 ( x-1)

x-1)( x(x+1) -2))

( x-1)( x^2 + x -2)

( x-1)( x^2 - x + 2x -2)

( x-1)( x( x-1) + 2 + x-1))

( x-1)( x-1)( x+2)
Answered by siddhartharao77
3

Answer:

(x - 1)²(x + 2)

Step-by-step explanation:

Given Equation is x³ - 3x + 2

= x³ + x² - x² - 2x - x + 2

= x³ + x² - 2x - x² - x + 2

= x(x² + x - 2) - 1(x² + x - 2)

= (x - 1)(x² + x - 2)

= (x - 1)(x² - x + 2x - 2)

= (x - 1)(x(x - 1) + 2(x - 1))

= (x - 1)(x - 1)(x + 2)

= (x - 1)²(x + 2).


Hope it helps!

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