Question

5% population of a town died due to some epidemic and thereafter 15% of the
remaining migrated from the town. If the population of town today in 80750, find the
population of the town in the beginning.​

Answer 1

Answer:

Let the population of the town, in the beginning, be “x”.

After 5% of the population died, remaining population = x – (5% * x) = 95x/100

After 15% of the remaining migrated from the town, the final remaining population

= [95x/100] – [15% * (95x/100)]

= [9500x – 1425x] / [100 * 100]

= 8075x / [100*100]  

The present population = 80750

Therefore, we have  

8075x / [100*100] = 80750

⇒ x = 80750 * 100 * 100 / 8075 = 1,00,000

Hence, the population of the town in the beginning is 1,00,000.

Answer 2

Answer:

Population of town in beginning = 100,000

Step-by-step explanation:

In the question,

Let the population of the town be, P = 100x

Percent of people died due to epidemic = 5%

Percent of people migrated from town = 15%

Population of the remaining town = 80750

So,

We can say that,

$100x-\dfrac{5}{100}(100x)=95x$

Therefore, remaining population after the epidemic is = 95x

Now,

After migration the population is given by,

$95x-(\dfrac{15}{100}\times 95x)=80750\\95x-14.25x=80750\\80.75x=80750\\x=1000$

Therefore, the Population of the town in the beginning is given by,

P = 100x = 100 x 1000 = 100,000