Question

(5 power 0 + 6 power -1) × 3 power 2.​

Answer 1

Answer:

(5⁰+6-¹)×3²

= (1+1/6)×9

=7/6×9

=21/2

Answer 2

(5⁰ + 6⁻¹) × 3²

To solve this we must apply laws of exponents. First we will apply these two laws of exponents for the brackets.

• a⁰ = 1

• $a^{-m} = \dfrac{1}{a^{m}}$

⇒ (5⁰ + 6⁻¹) × 3²

⇒ $(1+\dfrac{1}{6})\times 3^{2}$

Now we will find the LCM of the denominators in the fractions in the bracket. The LCM of 1 and 6 is 6 so using this value we will make the denominators equal.

⇒ $(1+\dfrac{1}{6})\times 3^{2}$

⇒ $(\dfrac{1\times 6 }{1\times 6 } +\dfrac{1}{6})\times 3^{2}$

⇒ $(\dfrac{6 }{6 } +\dfrac{1}{6})\times 3^{2}$

Now add the denominators to obtain the answer of the brackets.

⇒ $(\dfrac{6 }{6 } +\dfrac{1}{6})\times 3^{2}$

⇒ $\frac{7 }{6 }\times 3^{2}$

Now we'll find the value of 3².

3² = 3×3 = 9

⇒ $\dfrac{7 }{6 }\times 9$

⇒ $\dfrac{7 }{6 \div 3 }\times 9\div 3$

⇒ $\dfrac{7 }{2}\times 3$

⇒ $\dfrac{21}{2}$

$\bf \therefore (5^{0} + 6^{-1}) \times 3^{2} = \frac{21}{2}$

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