Math, asked by parmodrana274, 5 months ago

5. Product of two numbers is 91872. If one number is 198. Find the other.
6. Cost of 42 computers is * 1199940. Find the cost of 1 computer.​

Answers

Answered by Anonymous
0

Step-by-step explanation:

usual, prove it using the general heuristic that

X=YX=Y if and only if X⊆Y and X⊇Y.X⊆Y and X⊇Y.

In other words, take a generic element of A×(B−C)A×(B−C) and show that it also must be an element of (A×B)−(A×C)(A×B)−(A×C), and vice versa.

Answered by vedikasinghvs05
4

Answer:

5.) 464

6.)28,570

Step-by-step :

5. Given,

One number = 198

Let the other no be x

According to given condition,

=> 198 × x = 91872

=> x = 91872÷198

=> x = 464 Ans

6.

If cost of 42 computers is 1199940

Then cost of 1 computer is = 1199940÷42

= 28,570 Ans

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