5) Property of three
parallel lines and
A
B
their transversals.
Р
Q
If line AB line PQ
|| line MN
M
AP BQ
then
PM ON
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2
Answer:
40∘+u=180∘⇒u=140∘ω+u=180∘⇒ω=180°−u=40°∠z=70°(vertically opposite angles)
∠y+∠z=180°
⇒∠y=180°−∠z180°−70°=110°
⇒ω+x=180∘
∴x=140∘
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