Question

5. Prove : sec20 + cosec20 = sec20 x cosec20.​

Answer 1

Step-by-step explanation:

$lhs \\ = { \sec( \alpha ) }^{2} + { \cosec( \alpha ) }^{2} \\ = \frac{1}{ { \cos( \alpha ) }^{2} } + \frac{1}{ { \sin( \alpha ) }^{2} } \\ = \frac{ { \sin( \alpha ) }^{2} + { \cos( \alpha ) }^{2} }{ { \cos( \alpha ) }^{2} { \sin( \alpha ) }^{2} } \\ = \frac{1}{ { \cos( \alpha ) }^{2} { \sin( \alpha ) }^{2} } \\ = { \sec( \alpha ) }^{2} \times { \cosec( \alpha ) }^{2} \\ = rhs$

I hope my answer is satisfiable

If my answer is up to your mark then mark it as the brainiest answer.

Follow me for more

Don't forget to like