Question

5. Prove that cosh⁴x - sinh⁴x = cosh(2x).​

Answer 1

Answer:

your proof is as follows

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Step-by-step explanation:

$to \: prove \: that : \\ cos \: h {}^{4} x - sin \: h {}^{4} x = cos \: h(2x) \\ \\ = cos \: (h {}^{2} ) {}^{2} x - sin \: (h {}^{2} ) {}^{2} x \\ \\ = (cos \: h {}^{2} x + sin \: h {}^{2} x)(cos \: h {}^{2} x - sin \: h {}^{2} x) \\ \\ = 1(cos \: h {}^{2} x - sin \: h {}^{2} x) \\ \\ = cos \: h(2x)$