Question

+5 pts
F(x) ≡ 2x3 + px2 + qx + 6 where p and q are constants.
When f(x) is divided by (x+1), the remainder is 12. When f(x) is divided by (x-1) the
remainder is -6.
a) Find the value of p and the value of q.
where p and q are constants.

Answer 1

Answer:

So we know p=14*x and q=14*y for some values of x and y. x*y = 210/14 = 15. We can find the prime factors of 15 and use them to find possible values for p and q. For example 15 = 1*15, so one possible combination is p=14 and q=210.

Answer 2

Answer:

$p = 14 \: and \: q = 210 \: is \: ur \: answer$