Question

5(q-3)-3(q-2) =0 solve it​

Answer 1

Answer:

We have to solve it

Step-by-step explanation:

5(q-3)-3(q-2) =0

5q-15-3q+6= 0

2q-9 =0

2q = 9

q = 9/2

Hence proof//

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Answer 2

Given data: $5(q-3)-3(q-2)=0$

To Find: The required value for the equation $5(q-3)-3(q-2)=0$

Solution:

The distributive law of multiplication over subtraction,

$a(b-c)=ab-ac$

Hence, the equation $5(q-3)-3(q-2)=0$ can be written as,

$(5q-15)-(3q-6)=0$

$5q-15-3q+6=0$

Combine the like terms,

$5q-3q-15+6=0$

$2q-9=0$

Transpose value 9 to right,

$2q=9$

$q=\frac{9}{2}$

Therefore, the required value for the given equation $5(q-3)-3(q-2)=0$ is $q=\frac{9}{2}$