Question

5
Q21. In A ABBC. L A=( 3x + 1). L B= 2x, L C= (2x + 4'). Find the measure
of each angle.​

Answer 1

In ∆ABC,

$\angle { \sf{A}} + \angle { \sf{B}} + \angle { \sf{C}} = 180 \degree{ \sf}$

${ \sf{=> (3x + 1) + 2x + (2x + 4) = 180 }} \\ { \sf{ => 3x + 2x + 2x + 1 + 4 = 180 }} \\ { \sf{ =>7x + 5 = 180 }} \\ { \sf{ =>7x = 175 }} \\ { \sf{x = 25}}$

Hence,

${ \sf{ \angle{A} = (3x + 1) \degree = (3 \times 25 + 1) \degree = 76 \degree}}$

${ \sf{ \angle{B} = (2x) \degree = (2 \times 25) \degree = 50 \degree}}$

${ \sf{ \angle{C} = (2x + 4) \degree = (2 \times 25 + 4) \degree = 54 \degree}}$

Answer 2

Answer:

In ∆ABC,

=> (3x+1) + 2x + (2x+4) = 180°

=> 3x+2x + 2x+1 + 4 = 180°

=> 7x+5 = 180°

=> 7x = 175°

x = 25°.

Hence,

∠A = (3x+1)° = (3×25+1)° = 76°.

∠B = (2x)° = (2×25)° = 50°.

∠C = (2x+4)° = (2×25+4)° = 54°.

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