Question

5. R1= 3.00 ohms, R2 = 6.00 ohms and R3 = 5.00 ohms. The battery has negligible internal resistance. The current I2 through R2 is 4.00 A. What are the currents I1 and I3?

Answer 1

Answer:

answer is 2v

Explanation:

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Answer 2

Answer:

The currents $I_{1}$ and $I_{3}$ are 8A and 4.8A respectively.

Explanation:

Given:

$R_{1}$ = 3ohms

$R_{2}$ = 6ohms

$R_{3}$ = 5ohms

$I_{2}$ = 4A

Here,

The first resistance is denoted by $R_{1}$.

The second resistance is denoted by $R_{2}$.

The third resistance is denoted by $R_{3}$.

The current through $R_{1}$ is denoted by $I_{1}$.

The current through $R_{2}$ is denoted by $I_{2}$.

The current through $R_{3}$ is denoted by $I_{3}$.

The voltage across all resistance is denoted by V.

Now,

For $R_{2}$,

By the equation,

$V=I_{2} R_{2}$

$V = 4\times6\\V= 24V$

Then,

For $R_{1}$,

By the equation,

$V=I_{1} R_{1}$

$24 = I_{1} \times3\\I_{1} = 8A$

Then,

For $R_{3}$,

By the equation,

$V=I_{3} R_{3}$

$24 = I_{3} \times5\\I_{3} = 4.8A$

So, the currents $I_{1}$ and $I_{3}$ are 8A and 4.8A respectively.