Question

5. Ramit deposited * 80,000 in a bank which pays him 6% interest. After three years, he
withdraws the money and buys a car for 90,000. How much money is left with him?​

Answer 1

$\Large\sf\red{Given:}$

Principal, P = Rs. 80000

Rate of Interest = 6%

Time = 3years

$\Large\sf\red{To \:find:}$

Simple Interest

Money left

$\Large\sf\red{Solution:}$

$\tt\pink{P=80000}$

$\tt\pink{R=6\:percent}$

$\tt\pink{T=3\:years}$

$\Large\sf\orange{Formula\:used:}$

$\tt SI=\dfrac{8000\times 6\times 3}{100}$

$\tt=\dfrac{8000\times 6\times 3}{100}$

$\tt{ =8000\times 6\times 3}$

$\tt\green{ =14400}$

$\tt\blue{Therefore\:SI\:=14400}$

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$\Large\tt\pink{Amount = SI + Principal }$

$\tt\orange{14400+ 80000 = 944000 }$

$\tt\blue{Therefore\:Amount\:=944000}$

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$\tt\red{Amount\:Ramit\:has = 944000 }$

$\tt\red{He\: buys \:car= 90000}$

$\tt\red{Money \:left =944000-90000= 4400}$

$\bf\Large\blue{Therefore\:Money\:left\:=4400Rs}$

Answer 2

Step-by-step explanation:

$\huge{\underline{\mathrm{Question}}}$

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Ramit deposited 80,000 in a bank which pays him 6% interest. After three years, he withdraws the money and buys a car for 90,000. How much money is left with him?

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$\huge{\underline{\mathrm{Given}}}$

$\sf\blue{P = 80,000 }$

$\sf\blue{R = 6percent}$

$\sf\blue{ T = 3 years}$

$\huge{\underline{\mathrm{Explanation}}}$

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∴ SI = P × R × T

$⇛80000 × \frac{6}{100} \times 3$

$\huge{\underline{\mathrm{14,400}}}$

∴$Amount = SI + P$

⇛( 14,400 + 80,000 )

$\huge{\underline{\mathrm{94,400}}}$

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∴ $Amount \:Ramit \:has = Rupees 94,4000$

∴$He \:buys\: a\: car = 90,000$

∴ $Money\: left \:with\: him = rupees 4,400$

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