Question

5. Ramu runs around a rectangular park which is 34 m long and 16 m wide. How much distance will he cover in 5 rounds?
6. Anil cut a square paper with side 25 cm. He wants to put a tape on the border. How long will be the tape needed? Calculate the cost of the tape used if the price of the tape is ₹ 3 per cm.

Answer 1

$\qquad \: \: \: {\pmb{\underline{\underline{\frak{ Question \: 5 }}}}}$

Given :

• Length of Rectengular park = 34 m
• Breadth of Rectengular park = 16 m
• No. of Rounds = 5

$\\ \rule{200pt}{3pt}$

To Find :

• Distance Covered = ?

$\\ \rule{200pt}{3pt}$

Solution :

~ Formula Used :

${\purple{\dashrightarrow \: \: {\underbrace{\underline{\pmb{\red{\sf{ Perimeter{\small_{(Rectangle)}} = 2(L + B) }}}}}}}}$

Where :

• L = Length
• B = Breadth

$\\ \qquad{\rule{150pt}{1pt}}$

~ Calculating the Perimeter of Field :

${\dashrightarrow{\qquad{\sf { Perimeter{\small_{(Field)}} = 2(Length + Breadth)}}}} \\ \\ \ </p><p>{\dashrightarrow{\qquad{\sf { Perimeter{\small_{(Field)}} = 2(34 + 16)}}}} \\ \\ \ </p><p>{\dashrightarrow{\qquad{\sf { Perimeter{\small_{(Field)}} = 2 \times 50} }}} \\ \\ \ {\qquad{\textsf{ Perimeter of the field = {\green{\sf{ 100 \: m }}}}}}$

$\\ \qquad{\rule{150pt}{1pt}}$

~ Calculating the Distance Covered :

${\longmapsto{\qquad{\sf{ Distance \: Covered = Perimeter \times No. \: of \: Rounds }}}} \\ \\ \ {\longmapsto{\qquad{\sf{ Distance \: Covered = 100 \times 5 }}}} \\ \\ \ {\qquad{\textsf{ Distance Covered by Ramu = {\green{\sf{ 500 \: m }}}}}}$

$\\ \qquad{\rule{150pt}{1pt}}$

~ Therefore :

❝ Ramu covered a distance of 500 m . ❞

$\\ {\color{maroon}{\underline{\rule{100pt}{9pt}}}}{\blue{\underline{\rule{100pt}{9pt}}}}$

$\qquad \: \: \: {\pmb{\underline{\underline{\frak{ Question \: 6 }}}}}$

Given :

• Side of the square paper = 25 cm
• Rate of the Tape = ₹ 3 per cm

$\\ \rule{200pt}{3pt}$

To Find :

• Tape Required = ?
• Cost of the Tape = ?

$\\ \rule{200pt}{3pt}$

Solution :

~ Formula Used :

${\purple{\dashrightarrow \: \: {\underbrace{\underline{\pmb{\red{\sf{ Perimeter{\small_{(Square)}} = 4 \times Side }}}}}}}}$

$\\ \qquad{\rule{150pt}{1pt}}$

~ Calculating the Tape Required :

${\dashrightarrow{\qquad{\sf { Perimeter{\small_{(Square \: Paper)}} = 4 \times Side } }}} \\ \\ \ </p><p>{\dashrightarrow{\qquad{\sf { Perimeter{\small_{(Square \: Paper)}} = 4 \times 25 } }}} \\ \\ \ </p><p>{\qquad{\textsf{ Perimeter of the Square sheet = {\color{orange}{\sf{ 100 \: cm }}}}}}$

$\\ \qquad{\rule{150pt}{1pt}}$

~ Calculating the Cost of Tape :

${\longmapsto{\qquad{\sf{ Cost \: of \: Tape = Perimeter \times Rate{\small_{(Tape)}} }}}} \\ \\ \ {\longmapsto{\qquad{\sf{ Cost \: of \: Tape = 100 \times 3 }}}} \\ \\ \ {\qquad{\textsf{ Cost of the Tape Required = {\purple{\sf{ ₹ \: 300 }}}}}}$

$\\ \qquad{\rule{150pt}{1pt}}$

~ Therefore :

❝ Tape Required is 100 cm and the cost of tape is ₹ 300 . ❞

$\\ {\color{maroon}{\underline{\rule{100pt}{9pt}}}}{\blue{\underline{\rule{100pt}{9pt}}}}$

Answer 2

Question

Q/-Ramu runs around a rectangular park which is 34 m long and 16 m wide. How much distance will he cover in 5 rounds?

Given :

• Length of Rectengular park = 34 m
• Breadth of Rectengular park = 16 m

To Find :

• Distance Covered = ?

Formula Used :

${ \underline{ \boxed{ \frak{ \pink{Perimeter \: of \: rectangle=2(l+b) }}}}}$

Solution :

we know that

• Perimeter of rectangle=2(l+b)

★ Perimeter of rectangle:

$\\ \sf : \implies { Perimeter \: of \: rectangle= 2(l + b)}$

$\sf : \implies { Perimeter \: of \: rectangle= 2(34 + 16)}$

$\sf : \implies { Perimeter \: of \: rectangle= 2 \times 50}$

$\bf : \implies \red { Perimeter \: of \: rectangle= 100 \: m }$

★ Distance Covered in 5 rounds:

$\\ \sf : \implies {Distance \: Covered = Perimeter \times No. \: of \: Rounds }$

$\sf : \implies {Distance \: Covered = 100 \times 5 }$

$\bf : \implies \red { Distance \: Covered = 500 \: m}$

hence,Ramu covered a distance of 500 m

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Question:

Q/-Anil cut a square paper with side 25 cm. He wants to put a tape on the border. How long will be the tape needed? Calculate the cost of the tape used if the price of the tape is ₹ 3 per cm.

Given:

• Side of the square paper = 25 cm
• Rate of the Tape = ₹ 3 per cm

To Find :

• Tape Required = ?
• Cost of the Tape = ?

Formula Used:

${ \underline{ \boxed{ \frak{ \pink{Perimeter \: of \: square=4 \times sides }}}}}$

Solution:

we know that,

• Perimeter of Square = 4 × side

★ the Tape Required :

$\\ \sf : \implies { Perimeter \: of \: square= 4 \times sides}$

$\sf : \implies { Perimeter \: of \: square= 4 \times 25}$

$\bf : \implies \red{ Perimeter \: of \: square= 100}$

★ Cost of Tape :

$\\ \sf : \implies {Cost \: of \: Tape = Perimeter \times Rate }$

$\\ \sf : \implies {Cost \: of \: Tape = 100 \times 3 }$

$\bf : \implies \red{Cost \: of \: Tape = rs.300 }$

hence, Tape Required is 100 cm and the cost of tape is ₹ 300 .