Math, asked by umashankarlatha9, 8 months ago

5 rational and irrational number between 2.7 and 6.32​

Answers

Answered by divyankmaan
11

Answer:

Five irrational numbers between 2.7 and 6.3 are as follows:

  1. 3.101001000...
  2. 5.31323334...
  3. 2.98765432187654321...
  4. 4.11223344...
  5. 6.99989796...

Five rational numbers between 2.7 and 6.3 are as follows:

  1. 3
  2. 5.7
  3. 6.1
  4. 4.8
  5. 2.97

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Answered by NirmalPandya
0

5 rational numbers which are between 2.7 and 6.32, are 2.7+1=3.7, 2.7+2=4.7, 2.7+2.5=5.2,2.7+3=5.7, and 2.7+3.5=6.2 , and 5 irrational numbers which are between 2.7 and 6.32, are 2.866431762...., 3.7653663342...., 4.11223344..., 5.101001000....., and 5.31323334...

Given,

Two rational numbers: 2.7 and 6.32.

To Find,

5 rational and irrational numbers between 2.7 and 6.32.

Solution,

The method of finding 5 rational and irrational numbers between 2.7 and 6.32 is as follows -

The difference between 2.7 and 6.32 is 6.32-2.7=3.62.

So if we add 5 numbers to 2.7, which are less than 3.62 and greater than 0, we will get 5 rational numbers between 2.7 and 6.32.

5 numbers which are less than 3.62 and greater than 0, are 1, 2, 2.5, 3, and 3.5.

So 5 rational numbers which are between 2.7 and 6.32, are 2.7+1=3.7, 2.7+2=4.7, 2.7+2.5=5.2,2.7+3=5.7, and 2.7+3.5=6.2.

We know that irrational numbers are non-terminating and non-repeating numbers while represented in decimal representation.

So 5 irrational numbers which are between 2.7 and 6.32, are 2.866431762...., 3.7653663342...., 4.11223344..., 5.101001000....., 5.31323334...

Hence, 5 rational numbers which are between 2.7 and 6.32, are 2.7+1=3.7, 2.7+2=4.7, 2.7+2.5=5.2,2.7+3=5.7, and 2.7+3.5=6.2 , and 5 irrational numbers which are between 2.7 and 6.32, are 2.866431762...., 3.7653663342...., 4.11223344..., 5.101001000....., and 5.31323334...

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