Question

5 rational numbers between -3/2 and 5/3 plss with steps

Answer 1

please mark my answer as brainlylist

Answer 2

Step 1: Find the LCM (Least Common Multiple) of the denominators to make them equal.

$\begin{array}{r | l} 2 & 2,3 \\ \cline{2-2} 3 & 1,3 \\ \cline{2-2} & 1,1 \\ \end{array}$

LCM of 2 and 3 is ⇒ $2\times 3 = 6$

Step 2: Make the denominators equal.

$\frac{-3\times 3}{2\times3 } =\frac{-9}{6} \\\\\frac{5\times 2 }{3\times 2 } =\frac{10}{6}$

Step 3: List out the rational numbers between the two rational numbers.

$\texttt{Rational numbers between them are - }$

$\frac{-8}{6},\frac{-7}{6},\frac{-6}{6},\frac{-5}{6},\frac{-4}{6},\frac{-3}{6},\frac{-2}{6},\frac{-1}{6},0,\frac{1}{6},\frac{2}{6},\frac{3}{3},\frac{4}{3}, \frac{5}{3},\frac{6}{3},\frac{7}{3},\frac{8}{3} \ and \ \frac{9}{3}$

∴ Now, you can choose any 5 rational numbers from the list and write it down.

Additional Information :)

All of us know what a number line is. And the numbers we see here on the number line are called integers. On the right side of zero, we have positive integers and on the left, we have negative integers.

We are familiar with integers, but what about numbers like this -

$\frac{1}{3},\frac{-9}{8},etc$

Each of these is numbers, but we don't use them as often as we use counting numbers. Such numbers are called rational numbers. A rational number is represented in $\frac{p}{q}$ form, where p and q are known to be integers, are $q\neq 0$.