Math, asked by tillquote4360, 9 months ago

5.Ravish wanted to make a temporary shelter for
his car by making a box-like structure with
tarpaulin that covers al the four sides and the top of
the car (with the front face as flap which can be
rolled up). Assuming that the stitching margins are
very small, and therefore  negligible, how much
tarpaulin would be required to make the shelter of
height 2.5 m witt base dimensions 4 m ✕ 3 m?

Answers

Answered by akanshaagrwal23
2

Step-by-step explanation:

have you got your answer

Attachments:
Answered by kumarhemu893
0

Answer:

required shelter

2(bh+hl)+lb

2(4×2.5+3×2.5)+4×3

2(10+7.5)+12

25+12

47 m²

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