Question

5) Reduce -45/30 to the standard form.​

Answer 1

Question:-

Reduce -45/30 to the standard form.

Solution:-

$= > \frac{ - 45}{30} \\ = > \frac{ - 1 \times 3 \times 3 \times 5}{3 \times 2 \times 5} \\ = > \frac{ - 1 \times 3}{2} \\ = > \frac{ - 3}{2}$

Therefore, (-3/2) is the standard form, as the following fraction cannot be cancelled by a multiple, more.

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Answer 2

Before, finding the answer let's find out on how we can do the sum.

• For finding the standard form we reduce the fraction to their lowest term.

OR

• We can also divide it's Denominator and numerator by the HCF of the number.

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Given :

$\sf \: \dfrac{ - 45}{ - 30}$

To find :

Standard Form

Solution :

$\sf \: \dfrac{ - 45}{ - 30} = \dfrac{ - 45 \div 3}{ - 30 \div 3 } = \dfrac{ - 15}{10}$

$\sf \: \dfrac{ - 15}{10} = \dfrac{ - 15 \div 5}{10 \div 5} = \dfrac{ - 3}{ 2}$

OR

We can divide it by the HCF of 45 and 30.

HCF of 45 and 30 is 15.

$\sf \dfrac{ - 45}{30} = \dfrac{ - 45 \div 15}{ - 45 \div 15} = \dfrac{ - 3}{ 2}$

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Standard form :

• A rational number is said to be in the standard form if it's Denominator us a positive integer and denominator have no common factor except of 1.
• Hence, we Simply or Divide the Fraction with the HFC.