5. Rene is 6 years older than her younger sister. After 1 0 years, the sum of their ages will be 50 years. Find their present ages.
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Step-by-step explanation:
Let's have R be Rene's age.
R
And we have a younger sister who is 6 years younger than Rene:
R−6
In 10 years, the sum of their ages will be 50. So in 10 years Rene will be:
R+10
and her sister will be
R−6+10
and the two added together will be 50:
(R+10)+(R−6+10)=50
How old are they now?
(R+10)+(R−6+10)=50
2R+14=50
2R=36
R=18
and her sister is
R−6=18−6=12
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