5 resistances are arranged in the shape of a triangle each of 3 ohm . One of the resistor is also present on its altitude.
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Answered by
0
Answer:
To calculate resistance between A and B,we can treat resistors between BC and AB to be in series,
There equivalent hence is,
R
′
=R
BC
+R
AC
⟹R
′
=60+100=160Ω
Now this equivalent resistor is in parallel with R
AB
.
Equivalent of R
′
and R
AB
can be calculated using formula,
R
EQ
=
R
AB
+R
′
R
′
R
AB
⟹R
EQ
=
160+40
160×40
=32Ω
Answered by
1
Answer:
equivalent resistance = 1.5ohm
Step-by-step explanation:
we have,
S1=3+3=6ohm
S2=3+3=6ohm
1/P=1/S1+1/3+1/S2
=1/6+1/3+1/6
=2/6+1/3
=1/3+1/3
=2/3
P=3/2=1.5ohm
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