Question

5) Root of (x) = x² -3 - 2x is _________​

Answer 1

Answer:

${x}^{2} - 2x - 3 \\ \\ = x ^{2} - (3 - 1)x - 3 \\ \\ = {x}^{2} - 3x + x - 3 \\ \\ = x(x - 3) + 1(x - 3) \\ \\ = (x - 3)(x + 1) \\ \\ either \: x - 3 = 0 \\ \\ = > x = 3 \\ \\ or \: x + 1 = 0 \\ \\ x = - 1$

So tWo roots of the equation aRe 3 and ( - 1 )

hope it helps uH ✔

Answer 2

Answer:

ROOTS ARE 3 ,-1

THANKS .........