Question

(5+root27)+(4-root3)-(2root3-root6)​

Answer 1

Answer:

this is the answer I think it would help you

Answer 2

Answer:

$\huge\star \underline{ \boxed{ \purple{Answer}}}\star$

$\rm{5\:+\:\sqrt27\:+\:4\:-\:\sqrt3\:-\:2\sqrt3\:-\:\sqrt6}$

$\rm{=\:9\:-\:\sqrt6}$

Step-by-step explanation:

Given :-

$\rm{5\:+\:\sqrt27\:+\:4\:-\:\sqrt3\:-\:2\sqrt3\:-\:\sqrt6}$

To Find :-

$The\:simpler\:form\:of\:eq^n$

Solution :-

$\rm{5\:+\:\sqrt27\:+\:4\:-\:\sqrt3\:-\:2\sqrt3\:-\:\sqrt6}$

$\rm\green{First\:convert\:roots\:into\:simpler\:form}$

$\rm{5\:+\:3\sqrt3\:+\:4\:-\:\sqrt3\:-\:2\sqrt3\:-\:\sqrt2\times\sqrt3}$

$\rm{9\:+\:3\sqrt3\:-\:\sqrt3\:-\:2\sqrt3\:-\:\sqrt2\times\sqrt3}$

$\rm\green{Now\:take\:\sqrt3\:common}$

$\rm{9\:+\sqrt3(3\:-\:1\:-\:2\:-\:1\times\sqrt2)}$

$\rm{9\:+\sqrt3(0\:-\:\sqrt2)}$

$\rm{9\:+\sqrt3(-\sqrt2)}$

$\rm{9\:-\sqrt6}$

$\huge\rm\pink{Hence,}$

$\rm{9\:-\:\sqrt6\:is\:our\:required\:Answer}$

$\huge\mathfrak\red{Hope \: it \: helps \: you}$

$\huge\mathfrak\red{friend}$