Question

5. Saad throws a ball at an initial velocity of 42 ms!. Calculate the maximus
the ball car reach assuming the ball is caught at the same height at which it was
released (g = 9.8 m/s2)
​

Answer 1

Explanation:

WKT

• DISTANCE = ut-(1/2gt^2)
• u = -gt [v - u/ t = g] and v = 0........(2)

Given,

• u = 42m/s
• g = 9.8m/s^2

To find t, (2)

• t = -42/9.8
• t = 4.28 s

d = 42*4.2-1/2*9.8*17.64

= 176.4-86.4

• Therefore, d = 90 m