Question

(5) Sanjay gets fixed monthly income. Every year there is a certain increment in his salary.
After 4 years, his monthly salary was Rs. 4500 and after 10 years his monthly salary became 5400 rupees, then find his original salary and yearly increment.​

Answer 1

Answer:-

Given that :

• Sanjay gets fixed monthly income.

• After 4 years, his monthly salary was Rs. 4500 and after 10 years his monthly salary became 5400 rupees

To find :

• His original salary and yearly increment.

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Let the original salary be 'x' .

Let his yearly increment be 'y'

After 4 years, his salary was Rs. 4500

⇒ x + 4y = 4500

⇒ x = 4500 - 4y ....... equation[1]

After 10 years, his salary becomes 54,00.

Therefore,

⇒ x + 10y = 5400

⇒ 4500 - 4y + 10y = 5400

⇒ 6y = 900.

Putting the values in eq.[1],

⇒ x = 4500 - 4(150)

⇒ x = 4500 - 600 = 3900

Hence,

His original salary was Rs. 3900 and increment per year was 150 Rs.

Answer 2

SOLUTION:-

Given:

Sanjay gets fixed monthly income. Every year there is a certain increment in his salary. After 4 years, his monthly salary was Rs.4500, & after 10 years his monthly salary become Rs.5400.

To find:

The original salary and his yearly increment.

Explanation:

Let the original salary be Rs.R.

Let the yearly increment be Rs.M

According to the question:

• After 4 years his monthly salary Rs.4500

⇒ R+4M= 4500

⇒ R=4500-4M................(1)

&

• After 10 years his monthly salary Rs.5400

⇒ R+10M=5400...............(2)

Therefore,

Using substitution method:

Putting the value of R in equation (2), we get;

⇒ 4500-4M +10M=5400

⇒ 4500 +6M=5400

⇒ 6M= 5400-4500

⇒ 6M = 900

⇒ M=900/6

⇒ M= Rs.150

Putting the value of M in equation (1), we get;

R= 4500 - 4(150)

R= 4500- 600

R= Rs.3900.

Thus,

• The original salary of sanjay is Rs.3900.
• The yearly increment Rs.150.