Question

5 sec theta-12 cosec theta =0 find the values of sec theta, cos theta, sin theta...

Answer 1

Hey !!




Cosec ¢ = Hypotenuse / Perpendicular


And,


Sec ¢ = Hypotenuse / Base




Given :- 5 Sec ¢ - 12 Cosec ¢ = 0




5 Sec ¢ = 12 Cosec ¢




Cosec ¢ / Sec ¢ = 5/12




Hypotenuse / Perpendicular / Hypotenuse / Base = 5/12




Hypotenuse / Perpendicular × Base / Hypotenuse = 5/12




Base / Perpendicular = 5/12




Base = 5 and Perpendicular = 12


By Pythagoras theroem ,


( Hypotenuse )² = ( Base )² + ( Perpendicular)²



( Hypotenuse )² = (5)² + (12)²



( Hypotenuse )² = 169


Hypotenuse = √169


Hypotenuse = 13



Therefore,



Sec ¢ = Hypotenuse / Base = 13/5



Cos ¢ = Base / Hypotenuse = 5/13


Sin ¢ = Perpendicular/ Hypotenuse = 12/13