Math, asked by gargdeepansh12, 10 months ago

5/sec²theta + 2/(1+cot²theta) + 3 sin²theta

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Answered by sushant3649

0

the answer of this question is 1

Answered by sultan85

1

5/sec^o+2/(1+cot^2o)+3sin^2o

5cos^o+2/cosec^2o+3sin^2o

5cos^2o+2sin^2o+3sin^2o

5cos^2o+5sin^2o

5 (sin^2o+cos^2o)

5 (1)

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