Question

5 seco - 12 coseco=0
Find values of sec cos, sin.
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Answer 1

Step-by-step explanation:

Pls refer the above image for the ans....

Hope this helps u

Answer 2

Sino=12/13

Seco=13/5

Coso=5/13

From above question we get sino/coso=12/5

I.e. 1/coseco=sino and 1/seco=coso

By right angle theorem we get hypoteneous=13