5. Seven times a two-digit number equals four
times the number with digits reversed. Find
the number, if the sum of its digits is 3.
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(10x+y)7=4(10y+x)
70x + 7y = 40y + 4x
66x=33y
66x - 33y = 0
6x - 3y = 0
x+y=3
6x + 6y = 18
6x - 3y = 0
Subtract the two equations
9y =18
y=2
x=1
The no. is 12
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