Math, asked by divyeshhansoti, 8 months ago

5. Shobo's mother's present age is six times Shobo's present age. Shobo's age five
years from now will be one third of his mother's present age. What are their
present ages?
6. There is a narrow rectangular plot, reserved for a school, in Mahuli village. The
length and breadth of the plot are in the ratio 11:4. At the rate 5100 per metre it will
cost the village panchayat 75000 to fence the plot. What are the dimensions of
the plot?

Answers

Answered by Anonymous

Answer:

5Ans: Shobo's mother age is 6 times of Shobo. After 5yrs Shobo's age will be 1/3 of his mothers present age. We will solve this linear equation in two Variable to get the ages of Shobo and his mother. Hence Shobo's present age is 5yrs and present age of mother will be 5 × 6 = 30yrs.

6Ans:

Let the length and breadth's common ratio: x in metre

∴ Length :11x and Breadth :4x

Perimeter ⇒2(l+b)

=2(11x+4x)=30x

As per the question:

Cost of fencing plot at rate of Rs.100 per meter is Rs.75000

∴100× Perimeter =75000

3000x=75000

x=25

Length =11×x=11×25=275 m

Breadth =4x,=4×25=100 m

Step-by-step explanation:

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Answered by kashishtiwari2005

Answer:

5:What would you like to ask?

8th

Maths

Linear Equations in One Variable

Solving Linear Equations with Variable on Both Sides

Shobo's mother's present ag...

MATHS

Shobo's mother's present age is six times Shobo's present age. Shobo's age five years from now will be one third of the mother's present age. What are their present ages?

MEDIUM

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ANSWER

Let the present age of Shobo be x years .

Then, Shobo's mother's age =6x years

After 5 years: Shobo's age =(x+5) years

∴(x+5)=

×(6x)

On cross multiplying, we get

3×(x+5)=6x

⇒3x+15=6x

⇒3x−6x=−15

⇒−3x=−15

⇒x=5

6:Let the length and breadth's common ratio: x in metre