Question

5. Show that 3√2 is irrational, using the fact that √2 is irrational.

Standard:- 10

Content Quality Solution Required

❎ Don't Spamming ❎

Answer 1

Here is ur answer 

To show:3√2is an irrational number.
proof:
Let we first take 3√2 is rational number

and 
3√2=p/q (where p and q are integer & q≠0

then √2 =p/3q

{p/3q} is a rational number but this contradiction show that √2 is a irrational number so 

3√2 is a irrational number

I hope this help u!!!

Answer 2

Your answer is ---

Let, us assume that 3√2 is rational .

So, 3√2 = a/b , where a and b are integer and b ≠ 0

=> √2 = a/3b

Since, a/3b is rational because a and b are integer and b ≠ 0

therefore, √2 is also rational
[ °•° √2 = a/3b ]

But, thus contradict the fact that √2 is irrational .

So, this contradict is arise because our assumption is wrong .

Hence, 3√2 is irrational .

【 Hope it helps you 】