Question

5. Show that the polynomial 9x^2 + 6x + 4 has no real zeroes.plz tell some easy method with explanation​

Answer 1

Answer:

D = b^2 - 4ac

a = 9 ( x^2 coefficient )

b= 6( x coefficient )

c = 4 ( constant )

use the above formula

Step-by-step explanation:

D = 36- 4 (9)(4)

= 36 - 144

= - 108

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