Question

5.
Show that the polynomial x^- 2x + 5 has no real zeroes.​

Answer 1

Answer:

x^2 -2x+5

on comparing with the equation ax^2+bx+c

a=1

b=-2

c=5

if b^2-4ac<0

then the equation has no real root

-2^2-4(1)(5)

4-20

-15

Answer 2

Step-by-step explanation:

x^2 -2x+ 5

by using quadratic equation formula

$- b \: + or - whole \: root \: {b}^{2} - 4ac \: \div 2a$

-(-2) +/- (whole root (2)^2 - 4(1×5)

2 +/- (whole root (4-20))

2 +/-( root -16)

2 + -4 /2 or 2-(- 4) /2

-2/2 or 6/2

= -1 or 3 .

therefore the polynomial has no real roots.