Question

5. Sides of a triangle are in the ratio of 12:17:25 and its perimeter is 540cm. Find its area.
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Answer 1

Answer:

9000m²

Step-by-step explanation:

i hope it's helpful for you

Answer 2

$solution :$

$- - - - - - - - - - - - - - - - - \\ => \: let \: x \: be \: common \: ratio \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$therefore$

$sides \: of \: triangle \: will \: be : \: 12x \: \: 17x \: and \: 25 \: x$

$=> perimeter = \: 540 \: cm (given)$

$=> 12x \: + 17x + 25x = 540 \: cm \:$

$=> 54x \: = 540 \: cm$

$=> x \: = 10 \: cm$

$therefore \: sides \: of \: triangle :$

$a = 120 \: \: \: \: b = 170 \: \: \: c = 250 \: cms$

$=> 2 \: s = 540$

$=> s = 270 \: cm$

$a = \sqrt{ s(s - a)(s - b)(s - c)}$

$\sqrt{270(270 - 120)(270 - 170)(270 - 250)}$

$=> \sqrt{270 \times 150 \times 100 \times 20 \: cm \: ^{2} }$

$= > a = 9000 \: \: cm \: ^{2}$

$- - - - - - - - - - - - - - - -$

$hope \: it \: helps \: u \\ pls \: mark \: me \: as \: brainliest$