5 sin 50° sec 40° - 3 cos 59° cosec 31º.
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2
Explanation given below
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Step-by-step explanation:
=> 5 sin 50° sec(90°-50°) - 3 cos 59° cosec(90°-59°)
=>5 sin 50° cosec 50° - 3 cos 59° sec 59°
[Since cosec and sec are the complements of sec and cosec respectively]
=>5 sin 50° × 1/sin 50° - 3 cos 59° × 1/cos 59°
=>5 × 1 - 3×1
=>5 -3
=>2
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