(5 Sin 62/cos 28)-(2 sec 34/cosec 56
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Answer:3sin62/cos28 - sec42/cosec48
=3cos(90-62)/cos28 - cosec (90-42)/cosec48
=3cos28/cos28 - cosec48/cosec48
=3-1=2
it's help you.^_^
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10
Step-by-step explanation:
Here is your answer
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Hope it helps
May I know your name and class
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