Question

(5 Sin 62/cos 28)-(2 sec 34/cosec 56​

Answer 1

Answer:3sin62/cos28 - sec42/cosec48

=3cos(90-62)/cos28 - cosec (90-42)/cosec48

=3cos28/cos28 - cosec48/cosec48

=3-1=2

it's help you.^_^

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Here is your answer

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Hope it helps

May I know your name and class