Question

5 sin a-3 cosa If 5 tan a = 4 then 5 sin a + 2 cos a 1 4 2 5 b) d) 6 3 5 3 a)​

Answer 1

Answer:

Divide the numerator and denomenator by  cosθ

cosθ5sinθ+2cosθcosθ5sinθ−3cosθ⇒cosθ5sinθ+cosθ2cosθ3cosθ5sinθ−cosθ3cosθ⇒5tanθ+25tanθ−3

Substituting the value of 5tanθ, we get

⇒ 4+24−3=61