5.
sin“ A-cost A=1-2 cos’ A.
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Given to prove :-
- sin⁴ A - cos⁴ A = 1 - 2 cos² A
Answer :-
We have,
L.H.S = sin⁴ A - cos⁴ A
R.H.S = 1 - 2 cos² A
Therefore,
L.H.S = sin⁴ A - cos⁴ A
= (sin² A)² - (cos² A)²
= (sin² A + cos² A) (sin² A - cos² A)
By using the identity (sin² A + cos² A) = 1, we get,
= 1 (sin² A - cos² A)
By multiplying 1 with (sin² A - cos² A), we get,
= sin² A - cos² A
By using sin² A = (1 - cos² A), we get,
= (1 - cos² A) - cos² A
= 1 - 2 cos² A = R.H.S
Hence, Proved!
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Remember:-
- sin² A = (1 - cos² A)
- (sin² A + cos² A) = 1
rsagnik437:
Perfect! :)
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