Question

5 sin theta equals to 4 find the value of 1 + sin theta upon 1 minus sin​

Answer 1

$\huge{\fcolorbox{cyan}{pink}{Solution:-}}$

$\huge{\bf{Given:-}}$

$\: 5 \sin( \alpha ) = 4$

$\huge{\bf{To \: find:-}}$

$\frac{1 + \sin \alpha }{1 - \sin \alpha}$

Now,

$\implies \sin \alpha = \frac{4}{5}$

putting the value:-

$\implies\frac{1 + \frac{4}{5} }{1 - \frac{4}{5} } \\ \\ \implies \ \frac{ \frac{9}{5} }{ \frac{1}{5} } \\ \\ \implies \frac{9}{5} \times 5 \\ \\ \implies{ \boxed{ \pink{ 9}}}$

•°• Value is 9

Answer 2

Given:−

\: 5 \sin( \alpha ) = 45sin(α)=4

\huge{\bf{To \: find:-}}Tofind:−

\frac{1 + \sin \alpha }{1 - \sin \alpha}

1−sinα

1+sinα

Now,

\implies \sin \alpha = \frac{4}{5}⟹sinα=

5

4

putting the value:-

\begin{lgathered}\implies\frac{1 + \frac{4}{5} }{1 - \frac{4}{5} } \\ \\ \implies \ \frac{ \frac{9}{5} }{ \frac{1}{5} } \\ \\ \implies \frac{9}{5} \times 5 \\ \\ \implies{ \boxed{ \pink{ 9}}}\end{lgathered}

⟹

1−

5

4

1+

5

4

⟹

5

1

5

9

⟹

5

9

×5

⟹

9

•°• Value is 9