5 sin theta minus 12 cos theta = 0 find the value of sec theta and Cos theta
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Step-by-step explanation:
given- 5sina-12cosa=0
to find-sec a
5sina-12cosa=0
divide by cosa
5sina/cosa-12=0
5tana-12=0
5tana=12
squaring both sides
25tan^2a=144
tan^2a=144/25
we know 1+tan^2a=sec^a
sec^2a-1=144/25
sec^a=144/25+1
sec^a=169/25
seca=13/5
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