Question

5. Six cubes each with 12 cm edge are joined end to end. Find the surface area of the cuboid so formed​

Answer 1

Step-by-step explanation:

breadth of formed cuboid is 12 cm

height of formed cuboid is also 12 cm

but, length of cuboid is 12x6 cm = 72 cm

so, surface area = 2( lb + bh + hl )

= 2 ( 72x12 + 12x12 + 72x12 )

= 2 ( 864 + 144 + 864)

= 2( 1872)

= 3744

Answer 2

Given :- Six cubes each with 12 cm edge are joint end to end. Find the surface area of the resulting cuboid ?

Solution :-

given that,

→ Edge of each cube is = 12 cm.

when 6 cubes of same edge 12 cm are joined end to end ,

they formed a cuboid .

so,

Length of cuboid = sum of Edge of each cube = 6 * 12 = 72 cm. .

Breadth of cuboid = Edge of cube = 12 cm.

Height of cuboid = Edge of cube = 12 cm .

then,

→ The total surface area area of resulting cuboid = 2(L*B + BH * HL) = 2(72 * 12 + 12 * 12 + 12 * 72) = 2(864 + 144 + 864) = 2 * 1872 = 3744 cm².

Hence, the surface area of the resulting cuboid will be 3744 cm² .

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