Question

5. Slope of the line perpendicular to the line passing through the points (-3,8) and
(2,-2) is
(a) 1/3
(b) - 1/3
(C)-1/2
(d) 1/2​

Answer 1

Answer:

The equation of any straight line can be written as y=mx+c, where m

is its slope and c is its y - intercept.

Slope of the line passing through points (x

1

,y

1

) and (x

2

,y

2

) =

x

2

−x

1

y

2

−y

1

So, slope of the line joining (−5,6),(−6,5)=

5−6

−6+5

=1

Slope of the line perpendicular to this line =−1

So, equation of the required line will be y=−x+c

Since, this line passes through (2,3), on substituting (2,3) in the equation we get

3=−2+c

=>c=5

Hence, required equation of the line is y=−x+5 or x+y−5=0

Step-by-step explanation:

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