Question

5)Solve 5/12m-12= 48
6)what must be added to
2a3(to the power of 3) + 5a-a2(to the power of two) -6 to get a2(to the power of 2) -a(to the power of 3) + 1

(Algebra questions btw)
Pls answer ASAP

Answer 1

Answer:

$5) (5 \div 12x) - 12 = 48 \\5 \div 12x = 48 + 12 \\ 5 \div 12x = 50 \\ x = 5 \div 12 \times 1 \div 50 \\ x = 1 \div 12 \times 1 \div 10 \\ x = 1 \div 120$