Question

5. Solve by Gauss elimination method
x + 2y +2=3
2x + 3y + 3z = 10
3x - y + 2z = 13.​

Answer 1

Answer:

on further putting values you may find x and y

Answer 2

Answer:

The Value of $x=2, y=-1, z=3$

Step-by-step explanation:

Total Equations are 3

$x+2y+z=3== > (1)\\2x+3y+3z=10== > (2)\\3x-y+2z=13== > (3)$

Converting given equations into matrix form

1 2 1  3

2 3 3  10

3 -1 2  13

R2←R2-2×R1 =  

1 2 1  3

0 -1 1  4

3 -1 2  13

R3←R3-3×R1

=  

1 2 1  3

0 -1 1  4

0 -7 -1  4

R3←R3-7×R2

=  

1 2 1  3

0 -1 1  4

0 0 -8  -24

i.e.

x+2y+z=3→(1)

-y+z=4→(2)

-8z=-24→(3)

Now use back substitution method

From (3)

$-8z=-24\\== > z=\frac{-24}{-8}\\ =3$

From (2)

$-y+z=4\\== > -y+(3)=4\\== > -y+3=4\\== > -y=4-3\\== > -y=1\\== > y=-1$

From (1)

$x+2y+z=3\\== > x+2(-1)+(3)=3\\== > x+1=3\\== > x=3-1\\== > x=2$

Solution using back substitution method.

$x=2 ,y=-1 \ and \ z=3$

Reference link

• https://brainly.in/question/25946039
• https://brainly.in/question/42696828