Question

5.Solve it on a graph 4x-3y+4=0, 4x+3y-24=0 ​

Answer 1

4x−3y+4=0

⟹x=

4

−4+3y

Let, y=4, then x=

4

−4+3(4)

=2

Similarly, when y=0,x=−1

4x+3y−20=0

⟹x=

4

20−3y

Let, y=4, then x=

4

20−3(4)

=2

Similarly, when y=0,x=5

Plotting the above points on the graph, we get, the intersecting point i.e(2,4)

Area of the region bounded by these lines and x-axis =

2

1

×6units×4 units

=12 sq. units.