Question

5. Solve the following examples.

a. An electric pump has 2 kW power.
How much water will the pump lift
every minute to a height of 10 m?​

Answer 1

Answer:

20 kw

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Answer 2

Answer: Power, P = 2kw

Power, P = Work Done(W)

___________

Time Taken(T)

=W = P × T

For ever minute I.e 60's work done by the pump

is

W = 2 × 1000 × 60 = 12000J

Now this work is done in stored water as it is

potential energy. thus

mgh = 12000J