Question

5.Sovle:
a) 3(t-3) = 5 (2t+1)​

Answer 1

$\huge\red{\boxed{Question}}$

$3(t - 3) = 5(2t + 1)$

$\huge\red{\boxed{Answer}}$

$3t - 9 = 10t + 5$

$3t - 10t = 5 + 9$

$- 7t = 14$

$t = \frac{14}{ - 7}$

$t = - 2$

$\large{\boxed{∴ , The\:value\:of\:t\:is\:-2.}}$

$Hope \: \: this \: \: helps \: \: you \: !$

Answer 2

$\huge\bold{\mathbb{QUESTION}}$

Solve:

$3(t-3) = 5 (2t+1)$

$\huge\bold{\mathbb{TO\: FIND}}$

The value of $t.$

$\huge\bold{\mathbb{SOLUTION}}$

Let's find out the value of $t.$

$3(t-3) = 5 (2t+1)$

Remove parentheses.

$\implies 3t-9 = 10t+5$

Combine the like terms.

$\implies 3t-10t = 5+9$

$\implies -7t= 14$

$\implies -t = {\dfrac{14}{7}}$

$\implies -t = \cancel{\dfrac{14}{7}}$

$\implies -t = 2$

$\implies \underline{\boxed{\red{\mathfrak{t = -2}}}}$

$\huge\bold{\mathbb{HENCE}}$

$t = -2$

$\huge\bold{\mathbb{THEREFORE}}$

The value of $t$ is $-2.$

$\huge\bold{\mathbb{WE\:\,MADE\:\,IT\:\,!!}}$