Math, asked by bijukumarbiju442, 19 hours ago

5 = sqrt(7 ^ 2 + (y - 2) ^ 2) y=?​

Answers

Answered by rameshsimhadri91
1

Answer:

y= √4y-28

Step-by-step explanation:

sqrt(7 ^ 2 + (y - 2) ^ 2)=5

apply both sides sqrt then

{√(7^2+ (y-2)^2)}^2 =5^2

49 +(y-2)^2=25

(y-2)^2=25-49

y^2+4-4y= -24

y^2-4y=-28

y^2=4y-28

y=√4y-28

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