5 (square root 3x) + 2x^2 – (3x/2)How to rewrite this equation in LaTeX format
Answers
Answer:
We have to write given expression in latex format.
Given expression contain 3 terms.
First term is product of natural no and irrational no with square root.
In Latex for Square root we use this command " \sqrt{}" where 3x is inserted in braces.
⇒ First term in latex is written as " 5\sqrt{3x} "
Second term is product of natural no and an exponent
In Latex for Square (exponent) we use this command " ^{} " where power 2 is inserted in braces.
⇒ Second term in latex is written as " 2x^2 "
Third term is a rational no with p & q
In Latex for rational no, we use this command " \frac{}{} " where in 1st braces we insert numerator .i.e., p & in 2nd braces we insert denominattor .i.e.,q .
⇒ Third term in latex is written as " \frac{3x}{2} "
Therefore, Whole expression in latex is written as " 5\sqrt{3x}+2x^2-\frac{3x}{2} "
Answer:
Step-by-step explanation:
Please rewrite the following expression using LaTeX formatting:
5 (square root 3x) + 2x^2 – (3x/2)